kuangbin专题十三:基础计算几何
2021/5/3 10:26:47
本文主要是介绍kuangbin专题十三:基础计算几何,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
POJ2318 TOYS
思路:二分。
#include<iostream> #include<cstdio> #include<cstring> using namespace std; const int maxn = 5005; int n, m, x1, y1, x2, y2; int box[maxn]; struct Board{ int x1, x2; } board[maxn]; bool onLeft(int idx, int x, int y){ Board &b = board[idx]; return (b.x2 - b.x1) * (y - y1) - (y2 - y1) * (x - b.x1) < 0; } int findPosition(int x, int y){ int l = 0, r = n + 1; while(l + 1 != r){ int mid = (l + r) >> 1; if (onLeft(mid, x, y)) r = mid; else l = mid; } return l; } int main(){ while(scanf("%d", &n) && n){ memset(box, 0, sizeof(box)); scanf("%d%d%d%d%d", &m, &x1, &y1, &x2, &y2); board[0].x1 = board[0].x2 = x1; board[n+1].x1 = board[n+1].x2 = x2; for(int i = 1; i <= n; i++) scanf("%d%d", &board[i].x1, &board[i].x2); for(int i = 0; i < m; i++) { int x, y; scanf("%d%d", &x, &y); int position = findPosition(x, y); box[position]++; } for(int i = 0; i <= n; i++) printf("%d: %d\n", i, box[i]); printf("\n"); } return 0; }View Code
POJ2398 Toy Storage
思路:同上,记得给挡板排序。
#include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int maxn = 5005; int n, m, x1, y1, x2, y2; int box[maxn]; struct Cnt{ int cnt, idx; } cnt[maxn]; struct Board{ int x1, x2; } board[maxn]; bool onLeft(int idx, int x, int y){ Board &b = board[idx]; return (b.x2 - b.x1) * (y - y1) - (y2 - y1) * (x - b.x1) < 0; } int findPosition(int x, int y){ int l = 0, r = n + 1; while(l + 1 != r){ int mid = (l + r) >> 1; if (onLeft(mid, x, y)) r = mid; else l = mid; } return l; } bool cmpBoard(const Board& b1, const Board& b2){ if(b1.x1 == b2.x1) return b1.x2 < b2.x2; return b1.x1 < b2.x1; } int main(){ while(scanf("%d", &n) && n){ memset(box, 0, sizeof(box)); memset(cnt, 0, sizeof(cnt)); scanf("%d%d%d%d%d", &m, &x1, &y1, &x2, &y2); board[0].x1 = board[0].x2 = x1; board[n+1].x1 = board[n+1].x2 = x2; for(int i = 1; i <= n; i++) scanf("%d%d", &board[i].x1, &board[i].x2); sort(board, board + n + 2, cmpBoard); for(int i = 0; i < m; i++) { int x, y; scanf("%d%d", &x, &y); int position = findPosition(x, y); box[position]++; } for(int i = 0; i <= n; i++){ cnt[box[i]].cnt++; } printf("Box\n"); for(int i = 1; i <= m; i++) if(cnt[i].cnt) printf("%d: %d\n", i, cnt[i].cnt); } return 0; }View Code
这篇关于kuangbin专题十三:基础计算几何的文章就介绍到这儿,希望我们推荐的文章对大家有所帮助,也希望大家多多支持为之网!
- 2024-11-23Springboot应用的多环境打包入门
- 2024-11-23Springboot应用的生产发布入门教程
- 2024-11-23Python编程入门指南
- 2024-11-23Java创业入门:从零开始的编程之旅
- 2024-11-23Java创业入门:新手必读的Java编程与创业指南
- 2024-11-23Java对接阿里云智能语音服务入门详解
- 2024-11-23Java对接阿里云智能语音服务入门教程
- 2024-11-23JAVA对接阿里云智能语音服务入门教程
- 2024-11-23Java副业入门:初学者的简单教程
- 2024-11-23JAVA副业入门:初学者的实战指南