Creating Pandas DataFrames from Lists and Dictionaries

2021/5/15 10:55:20

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pandas 创建数据集

 

参考 [Creating Pandas DataFrames from Lists and Dictionaries - Practical Business Python](https://pbpython.com/pandas-list-dict.html)

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Introduction

Whenever I am doing analysis with pandas my first goal is to get data into a panda’s DataFrame using one of the many available options. For the vast majority of instances, I use read_excel , read_csv , or read_sql .

However, there are instances when I just have a few lines of data or some calculations that I want to include in my analysis. In these cases it is helpful to know how to create DataFrames from standard python lists or dictionaries. The basic process is not difficult but because there are several different options it is helpful to understand how each works. I can never remember whether I should use from_dict , from_records , from_items or the default DataFrame constructor. Normally, through some trial and error, I figure it out. Since it is still confusing to me, I thought I would walk through several examples below to clarify the different approaches. At the end of the article, I briefly show how this can be useful when generating Excel reports.

DataFrames from Python Structures

There are multiple methods you can use to take a standard python datastructure and create a panda’s DataFrame. For the purposes of these examples, I’m going to create a DataFrame with 3 months of sales information for 3 fictitious companies.

 accountJanFebMar
0 Jones LLC 150 200 140
1 Alpha Co 200 210 215
2 Blue Inc 50 90 95

Dictionaries

Before showing the examples below, I am assuming the following imports have been executed:

import pandas as pd
from collections import OrderedDict
from datetime import date

The “default” manner to create a DataFrame from python is to use a list of dictionaries. In this case each dictionary key is used for the column headings. A default index will be created automatically:

sales = [{'account': 'Jones LLC', 'Jan': 150, 'Feb': 200, 'Mar': 140},
         {'account': 'Alpha Co',  'Jan': 200, 'Feb': 210, 'Mar': 215},
         {'account': 'Blue Inc',  'Jan': 50,  'Feb': 90,  'Mar': 95 }]
df = pd.DataFrame(sales)
 FebJanMaraccount
0 200 150 140 Jones LLC
1 210 200 215 Alpha Co
2 90 50 95 Blue Inc

As you can see, this approach is very “row oriented”. If you would like to create a DataFrame in a “column oriented” manner, you would use from_dict

sales = {'account': ['Jones LLC', 'Alpha Co', 'Blue Inc'],
         'Jan': [150, 200, 50],
         'Feb': [200, 210, 90],
         'Mar': [140, 215, 95]}
df = pd.DataFrame.from_dict(sales)

Using this approach, you get the same results as above. The key point to consider is which method is easier to understand in your unique situation. Sometimes it is easier to get your data in a row oriented approach and others in a column oriented. Knowing the options will help make your code simpler and easier to understand for your particular need.

Most of you will notice that the order of the columns looks wrong. The issue is that the standard python dictionary does not preserve the order of its keys. If you want to control column order then there are two options.

First, you can manually re-order the columns:

df = df[['account', 'Jan', 'Feb', 'Mar']]

Alternatively you could create your dictionary using python’s OrderedDict .

sales = OrderedDict([ ('account', ['Jones LLC', 'Alpha Co', 'Blue Inc']),
          ('Jan', [150, 200, 50]),
          ('Feb',  [200, 210, 90]),
          ('Mar', [140, 215, 95]) ] )
df = pd.DataFrame.from_dict(sales)

Both of these approaches will give you the results in the order you would likely expect.

 accountJanFebMar
0 Jones LLC 150 200 140
1 Alpha Co 200 210 215
2 Blue Inc 50 90 95

For reasons I outline below, I tend to specifically re-order my columns vs. using an OrderedDict but it is always good to understand the options.

Lists

The other option for creating your DataFrames from python is to include the data in a list structure.

The first approach is to use a row oriented approach using pandas from_records . This approach is similar to the dictionary approach but you need to explicitly call out the column labels.

sales = [('Jones LLC', 150, 200, 50),
         ('Alpha Co', 200, 210, 90),
         ('Blue Inc', 140, 215, 95)]
labels = ['account', 'Jan', 'Feb', 'Mar']
df = pd.DataFrame.from_records(sales, columns=labels)

The second method is the from_items which is column oriented and actually looks similar to the OrderedDict example above.

sales = [('account', ['Jones LLC', 'Alpha Co', 'Blue Inc']),
         ('Jan', [150, 200, 50]),
         ('Feb', [200, 210, 90]),
         ('Mar', [140, 215, 95]),
         ]
df = pd.DataFrame.from_items(sales)

Both of these examples will generate the following DataFrame:

 accountJanFebMar
0 Jones LLC 150 200 140
1 Alpha Co 200 210 215
2 Blue Inc 50 90 95

Keeping the Options Straight

In order to keep the various options clear in my mind, I put together this simple graphic to show the dictionary vs. list options as well as row vs. column oriented approaches. It’s a 2X2 grid so I hope all the consultants are impressed!

Pandas DataFrame Creation Options

For the sake of simplicity, I am not showing the OrderedDict approach because the from_items approach is probably a more likely real world solution.

If this is a little hard to read, you can also get the PDF version.

Simple Example

This may seem like a lot of explaining for a simple concept. However, I frequently use these approaches to build small DataFrames that I combine with my more complicated analysis.

For one example, let’s say we want to save our DataFrame and include a footer so we know when it was created and who it was created by. This is much easier to do if we populate a DataFrame and write it to Excel than if we try to write individual cells to Excel.

Take our existing DataFrame:

sales = [('account', ['Jones LLC', 'Alpha Co', 'Blue Inc']),
         ('Jan', [150, 200, 50]),
         ('Feb', [200, 210, 90]),
         ('Mar', [140, 215, 95]),
         ]
df = pd.DataFrame.from_items(sales)

Now build a footer (in a column oriented manner):

from datetime import date

create_date = "{:%m-%d-%Y}".format(date.today())
created_by = "CM"
footer = [('Created by', [created_by]), ('Created on', [create_date]), ('Version', [1.1])]
df_footer = pd.DataFrame.from_items(footer)
 Created byCreated onVersion
0 CM 09-05-2016 1.1

Combine into a single Excel sheet:

writer = pd.ExcelWriter('simple-report.xlsx', engine='xlsxwriter')
df.to_excel(writer, index=False)
df_footer.to_excel(writer, startrow=6, index=False)
writer.save()
Sample Excel Auto Filter

The secret sauce here is to use startrow to write the footer DataFrame below the sales DataFrame. There is also a corresponding startcol so you can control the column layout as well. This allows for a lot of flexibility with the basic to_excel function.

Summary

Most pandas users quickly get familiar with ingesting spreadsheets, CSVs and SQL data. However, there are times when you will have data in a basic list or dictionary and want to populate a DataFrame. Pandas offers several options but it may not always be immediately clear on when to use which ones.

There is no one approach that is “best”, it really depends on your needs. I tend to like the list based methods because I normally care about the ordering and the lists make sure I preserve the order. The most important thing is to know the options are available so you can be smart about using the simplest one for your specific case.

On the surface, these samples may seem simplistic but I do find that it is pretty common that I use these methods to generate quick snippets of information that can augment or clarify the more complex analysis. The nice thing about data in a DataFrame is that it is very easy to convert into other formats such as Excel, CSV, HTML, LaTeX, etc. This flexibility is really handy for ad-hoc report generation.

Updates

  • 19-Nov-2018: As of pandas 0.23, DataFrame.from_items() has been deprecated. You can use DataFrame.from_dict(dict(items)) instead. If you want to preserve order, you can use DataFrame.from_dict(OrderedDict(items))


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