题目 1085: A+B for Input-Output Practice (I)

本文主要是介绍题目 1085: A+B for Input-Output Practice (I)，对大家解决编程问题具有一定的参考价值，需要的程序猿们随着小编来一起学习吧！

题目 1085: A+B for Input-Output Practice (I)

题目描述：
Your task is to Calculate a + b. Too easy?! Of course! I specially designed the problem for acm beginners. You must have found that some problems have the same titles with this one, yes, all these problems were designed for the same aim.
输入:
The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line.
输出:
For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.

 思路：还是多组数据进行测试a+b。
 我们可以通过循环来处理这个问题，我开始考虑的是用while=1进行循环
 处理，但输出超限 。所以我们反过来想让while中输入的不等于负数就解决了
 问题。

#include<stdio.h>
int main()
{
	int a,b;
	int sum;
	while(scanf("%d %d",&a,&b)!=-1)
	{
		sum=a+b;
		printf("%d\n",sum);
	}
	return 0;
}

这篇关于题目 1085: A+B for Input-Output Practice (I)的文章就介绍到这儿，希望我们推荐的文章对大家有所帮助，也希望大家多多支持为之网！