Oracle高级子查询
2021/6/9 19:25:10
本文主要是介绍Oracle高级子查询,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
高级子查询
子查询是嵌套在 SQL 语句中的另一个SELECT 语句
SELECT select_list FROM table WHERE expr operator (SELECT select_list FROM table);
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子查询 (内查询) 在主查询执行之前执行
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主查询(外查询)使用子查询的结果
子查询应用举例
查询工资大于149号员工工资的员工的信息
SELECT last_name FROM employees WHERE salary > (SELECT salary FROM employees WHERE employee_id = 149) ;
多列子查询
主查询与子查询返回的多个列进行比较
列比较
多列子查询中的比较分为两种:
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成对比较
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不成对比较
成对比较举例
查询与141号或174号员工的manager_id和department_id相同的其他员工的employee_id,manager_id, department_id
SELECT employee_id, manager_id, department_id FROM employees WHERE (manager_id, department_id) IN (SELECT manager_id, department_id FROM employees WHERE employee_id IN (141,174)) AND employee_id NOT IN (141,174);
在 FROM 子句中使用子查询
返回比本部门平均工资高的员工的last_name, department_id, salary及平均工资
SELECT a.last_name, a.salary, a.department_id, b.salavg FROM employees a, (SELECT department_id, AVG(salary) salavg FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary > b.salavg;
单列子查询表达式
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单列子查询表达式是在一行中只返回一列的子查询
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Oracle8i 只在下列情况下可以使用, 例如:
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ELECT 语句 (FROM 和 WHERE 子句)
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INSERT 语句中的VALUES列表中
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Oracle9i中单列子查询表达式可在下列情况下使用:
- DECODE 和 CASE
- SELECT 中除 GROUP BY 子句以外的所有子句中
单列子查询应用举例
在 CASE 表达式中使用单列子查询
显式员工的employee_id,last_name和location。其中,若员工department_id与location_id为1800的department_id相同,则location为’Canada’,其余则为’USA’。
select EMPLOYEE_ID, LAST_NAME, (case when DEPARTMENT_ID = (select DEPARTMENT_ID from DEPARTMENTS where LOCATION_ID = '1800') then 'Canada' else 'USA' end) as location from EMPLOYEES;
在 ORDER BY 子句中使用单列子查询
查询员工的employee_id,last_name,要求按照员工的department_name排序
select EMPLOYEE_ID, LAST_NAME from EMPLOYEES e order by (select DEPARTMENT_NAME from DEPARTMENTS d where e.DEPARTMENT_ID = d.DEPARTMENT_ID);
相关子查询
相关子查询按照一行接一行的顺序执行,主查询的每一行都执行一次子查询
相关子查询
SELECT column1, column2, ... FROM table1 WHERE column1 operator (SELECT colum1, column2 FROM table2 WHERE expr1 = .expr2);
子查询中使用主查询中的列
查询员工中工资大于本部门平均工资的员工的last_name,salary和其department_id
select e.LAST_NAME, e.SALARY, e.DEPARTMENT_ID from EMPLOYEES e, (select DEPARTMENT_ID, avg(SALARY) as avgs from EMPLOYEES group by DEPARTMENT_ID) d where e.DEPARTMENT_ID = d.DEPARTMENT_ID;
若employees表中employee_id与job_history表中employee_id相同的数目不小于2,输出这些相同id的员工的employee_id,last_name和其job_id
select EMPLOYEE_ID, LAST_NAME, JOB_ID from EMPLOYEES e where (select count(*) from JOB_HISTORY j where e.EMPLOYEE_ID = j.EMPLOYEE_ID)>=2;
EXISTS 操作符
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EXISTS 操作符检查在子查询中是否存在满足条件的行
- 如果在子查询中存在满足条件的行****:
- 不在子查询中继续查找
- 条件返回 TRUE
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如果在子查询中不存在满足条件的行****:
- 条件返回 FALSE
- 继续在子查询中查找
EXISTS 操作符应用举例
查询公司管理者的employee_id,last_name,job_id,department_id信息
select EMPLOYEE_ID, LAST_NAME, JOB_ID, DEPARTMENT_ID from EMPLOYEES e where exists(select 'X' from EMPLOYEES where MANAGER_ID = e.EMPLOYEE_ID); select EMPLOYEE_ID, LAST_NAME, JOB_ID, DEPARTMENT_ID from EMPLOYEES e where e.EMPLOYEE_ID in (select MANAGER_ID from EMPLOYEES);
查询departments表中,不存在于employees表中的部门的department_id和department_name
select DEPARTMENT_ID, DEPARTMENT_NAME from DEPARTMENTS d where (DEPARTMENT_ID, DEPARTMENT_NAME) not in (select DEPARTMENT_ID, DEPARTMENT_NAME from EMPLOYEES e where d.DEPARTMENT_ID = e.DEPARTMENT_ID); SELECT department_id, department_name FROM departments d WHERE NOT EXISTS (SELECT 'X' FROM employees WHERE department_id = d.department_id);
相关更新
UPDATE table1 alias1 SET column = (SELECT expression FROM table2 alias2 WHERE alias1.column = alias2.column);
使用相关子查询依据一个表中的数据更新另一个表的数据
UPDATE employees e SET department_name = (SELECT department_name FROM departments d WHERE e.department_id = d.department_id);
相关删除
DELETE FROM table1 alias1 WHERE column operator (SELECT expression FROM table2 alias2 WHERE alias1.column = alias2.column);
使用相关子查询依据一个表中的数据删除另一个表的数据
相关删除应用举例
删除表employees中,其与emp_history表皆有的数据
DELETE FROM employees E WHERE employee_id = (SELECT employee_id FROM emp_history WHERE employee_id = E.employee_id);
WITH 子句
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使用 WITH 子句, 可以避免在 SELECT 语句中重复书写相同的语句块
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WITH 子句将该子句中的语句块执行一次并存储到用户的临时表空间中
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使用 WITH 子句可以提高查询效率
WITH 子句应用举例
查询公司中各部门的总工资大于公司中各部门的平均总工资的部门信息
WITH dept_costs AS ( SELECT d.department_name, SUM(e.salary) AS dept_total FROM employees e, departments d WHERE e.department_id = d.department_id GROUP BY d.department_name), avg_cost AS ( SELECT SUM(dept_total)/COUNT(*) AS dept_avg FROM dept_costs) SELECT * FROM dept_costs WHERE dept_total > (SELECT dept_avg FROM avg_cost) ORDER BY department_name;
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