SQL - 5
2021/6/16 2:21:17
本文主要是介绍SQL - 5,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
8.行程和用户
需求:写一段 SQL 语句查出 2019年10月1日 至 2019年10月3日 期间非禁止用户的取消率。基于上表,你的 SQL 语句应返回如下结果,取消率(Cancellation Rate)保留两位小数。取消率的计算方式如下:(被司机或乘客取消的非禁止用户生成的订单数量) / (非禁止用户生成的订单总数)
Trips表:所有出租车的行程信息。每段行程有唯一键 Id,Client_Id 和 Driver_Id 是 Users 表中 Users_Id 的外键。Status 是枚举类型,枚举成员为 (‘completed’, ‘cancelled_by_driver’, ‘cancelled_by_client’)。
Id | Client_Id | Driver_Id | City_Id | Status | Request_at |
---|---|---|---|---|---|
1 | 1 | 10 | 1 | completed | 2019-10-01 |
2 | 2 | 11 | 1 | cancelled_by_driver | 2019-10-01 |
3 | 3 | 12 | 6 | completed | 2019-10-01 |
4 | 4 | 13 | 6 | cancelled_by_client | 2019-10-01 |
5 | 1 | 10 | 1 | completed | 2019-10-02 |
6 | 2 | 11 | 6 | completed | 2019-10-02 |
7 | 3 | 12 | 6 | completed | 2019-10-02 |
8 | 2 | 12 | 12 | completed | 2019-10-03 |
9 | 3 | 10 | 12 | completed | 2019-10-03 |
10 | 4 | 13 | 12 | cancelled_by_driver | 2019-10-03 |
Users 表:存所有用户。每个用户有唯一键 Users_Id。Banned 表示这个用户是否被禁止,Role 则是一个表示(‘client’, ‘driver’, ‘partner’)的枚举类型。
Users_Id | Banned | Role |
---|---|---|
1 | No | client |
2 | Yes | client |
3 | No | client |
4 | No | client |
10 | No | driver |
11 | No | driver |
12 | No | driver |
13 | No | driver |
展示效果:
Day | Cancellation Rate |
---|---|
2019-10-01 | 0.33 |
2019-10-02 | 0.00 |
2019-10-03 | 0.50 |
建表语句:
Create table If Not Exists Trips (Id int, Client_Id int, Driver_Id int, City_Id int, Status ENUM('completed', 'cancelled_by_driver', 'cancelled_by_client'), Request_at varchar(50)); Create table If Not Exists Users (Users_Id int, Banned varchar(50), Role ENUM('client', 'driver', 'partner')); Truncate table Trips; insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (1, 1, 10, 1, 'completed', '2019-10-01'); insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (2, 2, 11, 1, 'cancelled_by_driver', '2019-10-01'); insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (3, 3, 12, 6, 'completed', '2019-10-01'); insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (4, 4, 13, 6, 'cancelled_by_client', '2019-10-01'); insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (5, 1, 10, 1, 'completed', '2019-10-02'); insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (6, 2, 11, 6, 'completed', '2019-10-02'); insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (7, 3, 12, 6, 'completed', '2019-10-02'); insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (8, 2, 12, 12, 'completed', '2019-10-03'); insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (9, 3, 10, 12, 'completed', '2019-10-03'); insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (10, 4, 13, 12, 'cancelled_by_driver', '2019-10-03'); Truncate table Users; insert into Users (Users_Id, Banned, Role) values (1, 'No', 'client'); insert into Users (Users_Id, Banned, Role) values (2, 'Yes', 'client'); insert into Users (Users_Id, Banned, Role) values (3, 'No', 'client'); insert into Users (Users_Id, Banned, Role) values (4, 'No', 'client'); insert into Users (Users_Id, Banned, Role) values (10, 'No', 'driver'); insert into Users (Users_Id, Banned, Role) values (11, 'No', 'driver'); insert into Users (Users_Id, Banned, Role) values (12, 'No', 'driver'); insert into Users (Users_Id, Banned, Role) values (13, 'No', 'driver');
方法1:
select t.request_at as 'Day', Round(sum(if(t.status = 'complete',0,1))/count(t.status)) from Trips as t join Users as u on t.cilent_id = u.user.id and u.Banned = 'No' where t.request_at between '2019-10-01' AND '2019-10-03' group by t.request_at;
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