1.two sum
2021/7/17 23:35:49
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Question:
Given an array of integers nums
and an integer target
, return indices of the two numbers such that they add up to target
.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
You can return the answer in any order.
Example 1:
Input: nums = [2,7,11,15], target = 9 Output: [0,1] Output: Because nums[0] + nums[1] == 9, we return [0, 1].
Example 2:
Input: nums = [3,2,4], target = 6 Output: [1,2]
Example 3:
Input: nums = [3,3], target = 6 Output: [0,1]
Constraints:
2 <= nums.length <= 104
-109 <= nums[i] <= 109
-109 <= target <= 109
- Only one valid answer exists.
Answer:
class Solution(object): def twoSum(self, nums, target): """ :type nums: List[int] :type target: int :rtype: List[int] """ for i in range (len(nums)-1): j = i + 1 while j < len(nums): if nums[i] + nums[j] == target: return [i,j] j += 1 a=Solution() print(a.twoSum([2,7,11,15],9)) print(a.twoSum([3,2,4],6)) print(a.twoSum([3,3],6))
class Solution(object): def twoSum(self, nums, target): """ :type nums: List[int] :type target: int :rtype: List[int] """ for i in range (len(nums)-1): j = i + 1 while j < len(nums): if nums[i] + nums[j] == target: return [i,j] j += 1 a=Solution()print(a.twoSum([2,7,11,15],9))print(a.twoSum([3,2,4],6))print(a.twoSum([3,3],6))
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