mysql join带条件查询
2021/7/27 19:07:38
本文主要是介绍mysql join带条件查询,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
SELECT count(if(o.order_status=1,1,null)) as "symbol_1",count(if(o.order_status=2,1,null)) as "symbol_2",count(if(o.order_status=3,1,null)) as "symbol_3",count(if(o.order_status=4,1,null)) as "symbol_4",count(if(o.order_status=5,1,null)) as "symbol_5",count(if(o.order_status=6,1,null)) as "symbol_6",count(if(o.order_status=7,1,null)) as "symbol_7" FROM
ful_ky_order
oLEFT JOIN
ful_ky_contract
cON
c.
id=
o.
contract_idLEFT JOIN
ful_custom
cuON
c.
custom_id=
cu.
idleft join ful_admin_user
auON
au.
id=
cu.
user_id where au.name like "%张俊君%";
等同于
SELECT count(if(o.order_status=1,1,null)) as "symbol_1",count(if(o.order_status=2,1,null)) as "symbol_2",count(if(o.order_status=3,1,null)) as "symbol_3",count(if(o.order_status=4,1,null)) as "symbol_4",count(if(o.order_status=5,1,null)) as "symbol_5",count(if(o.order_status=6,1,null)) as "symbol_6",count(if(o.order_status=7,1,null)) as "symbol_7" FROM
ful_ky_order
oLEFT JOIN
ful_ky_contract
cON
c.
id=
o.
contract_idLEFT JOIN
ful_custom
cuON
c.
custom_id=
cu.
idjoin (select * from ful_admin_user where name like "%张俊君%")
auON
au.
id=
cu.
user_id;
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