4. 加入Benevolent Order of Programmer后，在BOP大会上，人们便可以通过加入者的真实姓名、头衔或秘密BOP姓名了解他（她）。请编写一个程序，可以使用真实姓名、头衔、秘密

本文主要是介绍4. 加入Benevolent Order of Programmer后，在BOP大会上，人们便可以通过加入者的真实姓名、头衔或秘密BOP姓名了解他（她）。请编写一个程序，可以使用真实姓名、头衔、秘密，对大家解决编程问题具有一定的参考价值，需要的程序猿们随着小编来一起学习吧！

// Benevolent Order of Programmer name structure 

struct bop {

    char fullname[strsize];      // real name

    char title[strsize];              // job title

    char bopname[strsize];     // secret BOP name

    int preference;                  // 0 = fullname, 1 = title, 2 = bopname

};

该程序创建一个由上述结构组成的小型数组，并将其初始化为适当的值。另外，该程序使用一个循环，让用户在下面的选项中进行选择：

a. display by name        b. display by title

c. display by bopname  d. display by preference

q. quit

注意，“display by preference”并不意味着显示成员的偏好，而是意味着根据成员的偏好来列出成员。例如，如果偏好号为1，则选择d将显示程序员的头衔。该程序的运行情况如下：

Benevolent Order Programmer Report 

a. display by name        b. display by title

c. display by bopname  d. display by preference

q. quit

Enter your choice: a

Wimp Macho

Raki Rhodes

Celia Laiter

Hoppy Hipman

Pat Hand

Next choice: d

Wimp Macho

Junior Programmer

MIPS 

Analyst Trainee

LOOPY

Next choice: q

Bye!
 

#include <iostream>
using namespace std;
const int strsize = 50;
struct bop {
	char fname[strsize];
	char title[strsize];
	char bopname[strsize];
	int pre;
};
int main() {
	bop info[5] = { 
		{"Wimp Macho", "W", "Wimp", 0}, 
		{"Raki Rhodes", "R", "Raki", 1}, 
		{"Celia Laiter", "C", "Celia", 2}, 
		{"Hoppy Hipman", "H", "Hoppy", 0}, 
		{"Pat Hand", "P", "Pat", 1} };
	char choice;
	cout << "benevolent order of progeammers report\n"
		<< "a)display by name  b)display by title\n"
		<< "c)display by bopname  d)display by preference\n"
		<< "q)quit\n";
	cout << "enter ur choice:";
	cin >> choice;
	while (choice!='q'){
		switch (choice) {
	    case 'a':
			for (int i = 0; i < 5; i++)
				cout << info[i].fname << endl;
			break;
		case 'b': 
			for (int i = 0; i < 5; i++)
				cout << info[i].title << endl;
			break;
		case 'c': 
			for (int i = 0; i < 5; i++)
				cout << info[i].bopname << endl;
			break;
		case 'd': {
			for (int i = 0; i < 5; i++){
				switch (info[i].pre) {
				case 0:
					cout << info[i].fname << endl;
					break;
				case 1:
					cout << info[i].title << endl;
					break;
				case 2:
					cout << info[i].bopname << endl;
					break;
				}
			}
		}break;
	    }
		cout << "next choice:\n";
		cin >> choice;
	}
	cout << "bye!";
	return 0;
}

网上答案 ：

C++ Primer Plus（第六版）编程练习答案 第6章 分支语句和逻辑运算符_清水河C罗——Leonardo-Liu-CSDN博客

// 6.4.cpp: 定义控制台应用程序的入口点。
//
 
#include "stdafx.h"
#include <iostream>
 
int main()
{
    using namespace std;
 
    cout << "Benevolent Order of Programmers Report" << endl;
    cout << "a. display by name\t\t";
    cout << "b. display by title\n";
    cout << "c. display by bopname\t\t";
    cout << "d. display by preference\n";
    cout << "q. quit\n";
 
    cout << "Enter your choice:";
    char choice;
    cin >> choice;
    while (choice != 'q')
    {
	switch (choice)
	{
	    case 'a': cout << "Wimp Macho\n" << "Raki Rhodes\n" << "Celia Laiter\n";
		cout << "Hoppy Hipman\n" << "Pat Hand\n";
		break;
	    case 'd': cout << "Wimp Macho\n" << "Junior Programmer\n" << "MIPS\n" << "Analyst Trainee\n" << "LOOPY\n";
		break;
	}
	cout << "Enter your choice:";
	cin >> choice;
    }
    cout << "Bye!\n";
    system("pause");
    return 0;
}

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