1115 Counting Nodes in a BST (30 分)
2021/9/7 14:06:12
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1115 Counting Nodes in a BST (30 分)
A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:
The left subtree of a node contains only nodes with keys less than or equal to the node’s key.
The right subtree of a node contains only nodes with keys greater than the node’s key.
Both the left and right subtrees must also be binary search trees.
Insert a sequence of numbers into an initially empty binary search tree. Then you are supposed to count the total number of nodes in the lowest 2 levels of the resulting tree.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤1000) which is the size of the input sequence. Then given in the next line are the N integers in [−1000,1000] which are supposed to be inserted into an initially empty binary search tree.
Output Specification:
For each case, print in one line the numbers of nodes in the lowest 2 levels of the resulting tree in the format:
n1 + n2 = n
where n1 is the number of nodes in the lowest level, n2 is that of the level above, and n is the sum.
Sample Input:
9 25 30 42 16 20 20 35 -5 28
Sample Output:
2 + 4 = 6
题目大意:给出排序二叉树序列,构造出二叉树后,求出最底下两层的数目和;
思路:链表存储,建树时统计最低两层的结点数
#include<iostream> using namespace std; struct node { int data, layer; node* lchild, * rchild; }; int lowest = -1, cnt1 = 0, above, cnt2 = 0; node* create(node*& root, int data, int layer) { if (root == NULL) { root = new node; root->data = data; root->lchild = root->rchild = NULL; if (layer > lowest) { lowest = layer; above = layer - 1; cnt2 = cnt1; cnt1 = 1; } else if (layer == lowest) { ++cnt1; } else if (layer == above) { ++cnt2; } } else if (data <= root->data) root->lchild = create(root->lchild, data, layer + 1); else root->rchild = create(root->rchild, data, layer + 1); return root; } int main() { int n; cin >> n; node* root = NULL; for (int i = 0;i < n;++i) { int data; cin >> data; root = create(root, data, 0); } cout << cnt1 << " + " << cnt2 << " = " << cnt1 + cnt2 << endl; return 0; }
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