List 集合 remove 对象时出现 ConcurrentModificationException

2021/9/7 23:06:58

本文主要是介绍List 集合 remove 对象时出现 ConcurrentModificationException,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!

在一次做项目的过程中要遍历 list 集合,然后根据条件删除 list 集合中不需要的对象,尝试了 list.remove() 方法,根本达不到目的,最后在网上看了几个帖子后才知道,要想根据条件删除 list 集合里面的对象,一定要使用 Iterator 遍历删除

如下示例

public class ListDemo {
    public static void main(String[] args) {
        List<Fruit> fruitList = new ArrayList<>();
        fruitList.add(new Fruit(1, "apple", "红色", 120.00));
        fruitList.add(new Fruit(2, "orange", "黄色", 140.00));
        fruitList.add(new Fruit(3, "guava", "灰色", 160.00));
        fruitList.add(new Fruit(4, "pear", "黄色", 180.00));
        fruitList.add(new Fruit(5, "mango", "黄色", 240.00));
        fruitList.add(new Fruit(6, "watermelon", "绿色", 260.00));

        if (Objects.nonNull(fruitList) && !fruitList.isEmpty()) {
            for (Fruit fruit : fruitList) {
                if (Objects.equals(fruit.getColor(), "黄色")) {
                    fruitList.remove(fruit);
                }
            }
        }
    }
}

执行上面的代码时会出现如下报错

对于 List 集合来说,如果你想移除 List 集合中的元素,必须要使用 Iterator 进行迭代遍历

public class ListDemo {
    public static void main(String[] args) {
        List<Fruit> fruitList = new ArrayList<>();
        fruitList.add(new Fruit(1, "apple", "红色", 120.00));
        fruitList.add(new Fruit(2, "orange", "黄色", 140.00));
        fruitList.add(new Fruit(3, "guava", "灰色", 160.00));
        fruitList.add(new Fruit(4, "pear", "黄色", 180.00));
        fruitList.add(new Fruit(5, "mango", "黄色", 240.00));
        fruitList.add(new Fruit(6, "watermelon", "绿色", 260.00));

        if (Objects.nonNull(fruitList) && !fruitList.isEmpty()) {
            ListIterator<Fruit> iterator = fruitList.listIterator();
            while(iterator.hasNext()){
                // 注意,进行元素移除的时候只能出现一次 iterator.next()
                if(Objects.equals(iterator.next().getColor(),"黄色")){
                    iterator.remove();
                }
            }
        }
    }
}

  

 



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