XXI Open Cup named after E.V. Pankratiev. Grand Prix of Korea

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C

知道这个定理：

Theorem. A graph \(G\) is strongly connected if and only if it can be constructed using the following procedure:

1. Start with \(N\) isolated vertices. Pick any vertex \(v\), and let \(S = \{v\}\).
2. Repeat the following until \(S = V(G)\):
   (a) Pick two vertices \(v\) and \(u\in S\). The two vertices can be the same.
   (b) Pick zero or more distinct vertices \(w_1, \cdots, w_k \notin S\).
   (c) Connect \(v\rightarrow w_1 \rightarrow \cdots \rightarrow w_k \rightarrow u\), and put \(w_1 \cdots w_k\) into \(S\).

然后就可以 xjb 状压 dp 了，题解给的第四维可以省掉

G

dp of dp, TODO: bzoj ATGC LCS by clj?

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