1992和2006年国家标准学科分类和代码存入MySQL数据库
2021/11/8 2:09:56
本文主要是介绍1992和2006年国家标准学科分类和代码存入MySQL数据库,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
数据表
代码
1 import pandas as pd 2 import pymysql 3 4 5 def get_subject_1992(): 6 res={} 7 the_former_code = "" 8 layer1_code = "" # 一位 9 layer1_name = "" 10 layer2_code = "" # 三位 11 layer2_name = "" # 三位 12 layer3_code = "" # 五位 13 layer3_name = "" 14 layer4_code = "" # 七位 15 layer4_name = "" # 七位 16 df = pd.read_excel("std_subject_1992.xlsx") 17 for i in range(len(df.values)): 18 item=df.values[i] 19 # print(item[0],item[1]) 20 if (len(str(item[0])) == 1): 21 layer1_code = str(item[0]) 22 layer1_name = item[1] 23 # print(layer1_code,layer1_name) 24 if (len(str(item[0])) == 3): 25 layer2_code = str(item[0]) 26 layer2_name = item[1] 27 # print(layer2_code, layer2_name) 28 if (len(str(item[0])) == 5): 29 layer3_code = str(item[0]) 30 layer3_name = item[1] 31 if(i!=(len(df.values)-1)): 32 if(len(str(df.values[i+1][0]))!=7): 33 # print(layer1_code + layer3_code,layer1_name + "·" + layer2_name + "·" +layer3_name) 34 res.update({layer1_code + layer3_code+"00":layer1_name + "·" + layer2_name + "·" +layer3_name}) 35 # print(layer3_code, layer3_name) 36 if (len(str(item[0])) == 6): 37 layer4_code = str(item[0])+"0" 38 layer4_name = item[1] 39 # print(layer4_code, layer4_name) 40 if (layer4_code[:5] == layer3_code): 41 # print(layer1_code + layer4_code,layer1_name + "·" + layer2_name + "·" + layer3_name + "·" + layer4_name) 42 res.update({layer1_code + layer4_code:layer1_name + "·" + layer2_name + "·" + layer3_name + "·" + layer4_name}) 43 if (len(str(item[0])) == 7): 44 layer4_code = str(item[0]) 45 layer4_name = item[1] 46 # print(layer4_code, layer4_name) 47 if (layer4_code[:5] == layer3_code): 48 # print(layer1_code + layer4_code,layer1_name + "·" + layer2_name + "·" + layer3_name + "·" + layer4_name) 49 res.update({layer1_code + layer4_code:layer1_name + "·" + layer2_name + "·" + layer3_name + "·" + layer4_name}) 50 return res 51 52 """ 53 --------------------------------------------------------------------------------------- 54 """ 55 def get_subject_2009(): 56 res={} 57 the_former_code = "" 58 layer1_code = "" # 一位 59 layer1_name = "" 60 layer2_code = "" # 三位 61 layer2_name = "" # 三位 62 layer3_code = "" # 五位 63 layer3_name = "" 64 layer4_code = "" # 七位 65 layer4_name = "" # 七位 66 df = pd.read_excel("std_subject_2009.xlsx") 67 for i in range(len(df.values)): 68 item=df.values[i] 69 # print(item[0],item[1]) 70 if (len(str(item[0])) == 1): 71 layer1_code = str(item[0]) 72 layer1_name = item[1] 73 # print(layer1_code,layer1_name) 74 if (len(str(item[0])) == 3): 75 layer2_code = str(item[0]) 76 layer2_name = item[1] 77 # print(layer2_code, layer2_name) 78 if (len(str(item[0])) == 5): 79 layer3_code = str(item[0]) 80 layer3_name = item[1] 81 if(i!=(len(df.values)-1)): 82 if(len(str(df.values[i+1][0]))!=7): 83 # print(layer1_code + layer3_code,layer1_name + "·" + layer2_name + "·" +layer3_name) 84 res.update({layer1_code + layer3_code+"00":layer1_name + "·" + layer2_name + "·" +layer3_name}) 85 if (len(str(item[0])) == 7): 86 layer4_code = str(item[0]) 87 layer4_name = item[1] 88 # print(layer4_code, layer4_name) 89 if (layer4_code[:5] == layer3_code): 90 # print(layer1_code + layer4_code,layer1_name + "·" + layer2_name + "·" + layer3_name + "·" + layer4_name) 91 res.update({layer1_code + layer4_code:layer1_name + "·" + layer2_name + "·" + layer3_name + "·" + layer4_name}) 92 return res 93 """ 94 --------------------------------------------------------------------------------------------------------------- 95 """ 96 def get_conn(): 97 """ 98 :return: 连接,游标 99 """ 100 # 创建连接 101 conn = pymysql.connect(host="127.0.0.1", 102 user="root", 103 password="000429", 104 db="data_cleaning", 105 charset="utf8") 106 # 创建游标 107 cursor = conn.cursor() # 执行完毕返回的结果集默认以元组显示 108 return conn, cursor 109 110 def close_conn(conn, cursor): 111 if cursor: 112 cursor.close() 113 if conn: 114 conn.close() 115 116 117 def into_mysql(): 118 global conn, cursor 119 res=get_subject_2009() 120 for k,v in res.items(): 121 print(k,v) 122 try: 123 conn,cursor=get_conn() 124 SQL="insert into std_subject_2009 (year,subject_code,subject_name) values (2009,'"+k+"','"+v+"')" 125 cursor.execute(SQL) 126 conn.commit() 127 except: 128 print(k,v+" 插入失败!") 129 conn,cursor.close() 130 return None 131 if __name__ == '__main__': 132 into_mysql()
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