java实现CGS2000大地坐标和WGS84经纬度坐标互转,亲测准确
2021/11/18 17:10:03
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WGS84转CGS2000
中央子午线需要根据实际设置,参数为经度,纬度,输出值为经度(x),纬度(y)
public static Point WGS84ToCGS2000(double longitude, double latitude)//参数 经度,纬度 { Point pt = null; double[] output = new double[2]; double longitude1,latitude1, longitude0, X0,Y0, xval,yval; //NN曲率半径,测量学里面用N表示 //M为子午线弧长,测量学里用大X表示 //fai为底点纬度,由子午弧长反算公式得到,测量学里用Bf表示 //R为底点所对的曲率半径,测量学里用Nf表示 double a,f, e2,ee, NN, T,C,A, M, iPI; iPI = 0.0174532925199433; //3.1415926535898/180.0; a=6378137.0; f=1/298.257222101; //CGCS2000坐标系参数 //a=6378137.0; f=1/298.2572236; //wgs84坐标系参数 longitude0 = 117;//中央子午线 根据实际进行配置 longitude0 = longitude0 * iPI ;//中央子午线转换为弧度 longitude1 = longitude * iPI ; //经度转换为弧度 latitude1 = latitude * iPI ; //纬度转换为弧度 e2=2*f-f*f; ee=e2*(1.0-e2); NN=a/Math.sqrt(1.0-e2*Math.sin(latitude1)*Math.sin(latitude1)); T=Math.tan(latitude1)*Math.tan(latitude1); C=ee*Math.cos(latitude1)*Math.cos(latitude1); A=(longitude1-longitude0)*Math.cos(latitude1); M=a*((1-e2/4-3*e2*e2/64-5*e2*e2*e2/256)*latitude1-(3*e2/8+3*e2*e2/32+45*e2*e2 *e2/1024)*Math.sin(2*latitude1) +(15*e2*e2/256+45*e2*e2*e2/1024)*Math.sin(4*latitude1)-(35*e2*e2*e2/3072)*Math.sin(6*latitude1)); xval = NN*(A+(1-T+C)*A*A*A/6+(5-18*T+T*T+72*C-58*ee)*A*A*A*A*A/120); yval = M+NN*Math.tan(latitude1)*(A*A/2+(5-T+9*C+4*C*C)*A*A*A*A/24 +(61-58*T+T*T+600*C-330*ee)*A*A*A*A*A*A/720); X0 = 500000L; Y0 = 0; xval = xval+X0; yval = yval+Y0; //转换为投影 output[0] = xval; output[1] = yval; pt = new Point(output[0],output[1]); return pt; }
CGS2000转WGS84
中央子午线需根据实际设置,输入参数为纬度,经度,输出result的顺序为result[0]纬度(y),result[1]经度(x)
private static double formatby6(double num) { String result = String.format("%.6f", num); return Double.valueOf(result); } //2000转84 public static Point CGS2000ToWGS84(double X, double Y) { Point pt = null; double L0 = 117;//中央子午线需根据实际情况设置 double lat ,lon; Y-=500000; double [] result = new double[2]; double iPI = 0.0174532925199433;//pi/180 double a = 6378137.0; //长半轴 m double b = 6356752.31414; //短半轴 m double f = 1/298.257222101;//扁率 a-b/a double e = 0.0818191910428; //第一偏心率 Math.sqrt(5) double ee = Math.sqrt(a*a-b*b)/b; //第二偏心率 double bf = 0; //底点纬度 double a0 = 1+(3*e*e/4) + (45*e*e*e*e/64) + (175*e*e*e*e*e*e/256) + (11025*e*e*e*e*e*e*e*e/16384) + (43659*e*e*e*e*e*e*e*e*e*e/65536); double b0 = X/(a*(1-e*e)*a0); double c1 = 3*e*e/8 +3*e*e*e*e/16 + 213*e*e*e*e*e*e/2048 + 255*e*e*e*e*e*e*e*e/4096; double c2 = 21*e*e*e*e/256 + 21*e*e*e*e*e*e/256 + 533*e*e*e*e*e*e*e*e/8192; double c3 = 151*e*e*e*e*e*e*e*e/6144 + 151*e*e*e*e*e*e*e*e/4096; double c4 = 1097*e*e*e*e*e*e*e*e/131072; bf = b0 + c1*Math.sin(2*b0) + c2*Math.sin(4*b0) +c3*Math.sin(6*b0) + c4*Math.sin(8*b0); // bf =b0+c1*sin2b0 + c2*sin4b0 + c3*sin6b0 +c4*sin8b0 +... double tf = Math.tan(bf); double n2 = ee*ee*Math.cos(bf)*Math.cos(bf); //第二偏心率平方成bf余弦平方 double c = a*a/b; double v=Math.sqrt(1+ ee*ee*Math.cos(bf)*Math.cos(bf)); double mf = c/(v*v*v); //子午圈半径 double nf = c/v;//卯酉圈半径 //纬度计算 lat=bf-(tf/(2*mf)*Y)*(Y/nf) * (1-1/12*(5+3*tf*tf+n2-9*n2*tf*tf)*(Y*Y/(nf*nf))+1/360*(61+90*tf*tf+45*tf*tf*tf*tf)*(Y*Y*Y*Y/(nf*nf*nf*nf))); //经度偏差 lon=1/(nf*Math.cos(bf))*Y -(1/(6*nf*nf*nf*Math.cos(bf)))*(1+2*tf*tf +n2)*Y*Y*Y + (1/(120*nf*nf*nf*nf*nf*Math.cos(bf)))*(5+28*tf*tf+24*tf*tf*tf*tf)*Y*Y*Y*Y*Y; result[0] =formatby6(lat/iPI); result[1] =formatby6(L0+lon/iPI); //System.out.println(result[1]+","+result[0]); pt = new Point(result[1],result[0]); return pt; }
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