Python——逻辑异或运算及图示(采用逻辑异或运算方法实现)(tkinter实现)
2021/11/23 17:40:18
本文主要是介绍Python——逻辑异或运算及图示(采用逻辑异或运算方法实现)(tkinter实现),对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
目录- 1.difortu.py
- 2.结果示例
本功能作者:
1.CSDN用户(philo42),philo42主页
2.CSDN用户(TDTX),TDTX主页
博客园用户(TDTX),TDTX主页
1.difortu.py
def difortu(): import tkinter as tk windor=tk.Tk() windor.title('逻辑异或及图示') windor.geometry('500x500') def qor(): tx5.delete(1.0,'end') tx6.delete(1.0,'end') tx7.delete(1.0,'end') tx.delete(0.0,tk.END) q=eval(ent1.get()) p=eval(ent2.get()) if q == p: tx.insert('insert',0) tx7.insert('insert',0) else: tx.insert('insert',1) tx7.insert('insert',1) tx5.insert('insert',q) tx6.insert('insert',p) lb1=tk.Label(windor,text='输入q值:',fg='blue',width=10,height=2) lb1.place(x=100,y=30) ent1=tk.Entry(windor,width=5) ent1.place(x=170,y=35) lbs=tk.Label(windor,text='⊕',fg='red') lbs.place(x=220,y=35) lb2=tk.Label(windor,text='输入p值:',fg='blue',width=10,height=2) lb2.place(x=235,y=30) ent2=tk.Entry(windor,width=5) ent2.place(x=300,y=35) bt1=tk.Button(windor,text='求解q⊕p',command=qor) bt1.place(x=200,y=70) lbf=tk.Label(windor,text='-----------------------------------------------') lbf.place(x=110,y=95) lb3=tk.Label(windor,text='q⊕p值为:',fg='blue',bg='yellow') lb3.place(x=200,y=120) tx=tk.Text(windor,width=2,height=1) tx.place(x=230,y=150) canvas=tk.Canvas(windor,bg='white',height=100,width=280) line=canvas.create_line(50,40,140,40) line=canvas.create_line(80,40,70,46) line=canvas.create_line(80,40,70,34) line=canvas.create_line(50,60,140,60) line=canvas.create_line(80,60,70,66) line=canvas.create_line(80,60,70,54) arc = canvas.create_arc(100,25,140,75,start=270,extent=180,style=tk.ARC) arc = canvas.create_arc(80,25,130,75,start=270,extent=180,style=tk.ARC) #arc = canvas.create_arc(100,25,170,75,start=270,extent=180,style=tk.ARC) arc = canvas.create_arc(60,25,180,75,start=270,extent=180,style=tk.ARC) line=canvas.create_line(180,50,250,50) line=canvas.create_line(210,50,200,56) line=canvas.create_line(210,50,200,44) canvas.place(x=100,y=200) lb4=tk.Label(windor,text='q') lb4.place(x=135,y=210) lb5=tk.Label(windor,text='p') lb5.place(x=135,y=270) lb6=tk.Label(windor,text='q⊕p') lb6.place(x=280,y=220) tx5=tk.Text(windor,width=6,height=1) tx5.place(x=158,y=210) tx6=tk.Text(windor,width=6,height=1) tx6.place(x=158,y=270) tx7=tk.Text(windor,width=6,height=1) tx7.place(x=320,y=220) windor.mainloop
2.结果示例
这篇关于Python——逻辑异或运算及图示(采用逻辑异或运算方法实现)(tkinter实现)的文章就介绍到这儿,希望我们推荐的文章对大家有所帮助,也希望大家多多支持为之网!
- 2025-01-03用FastAPI掌握Python异步IO:轻松实现高并发网络请求处理
- 2025-01-02封装学习:Python面向对象编程基础教程
- 2024-12-28Python编程基础教程
- 2024-12-27Python编程入门指南
- 2024-12-27Python编程基础
- 2024-12-27Python编程基础教程
- 2024-12-27Python编程基础指南
- 2024-12-24Python编程入门指南
- 2024-12-24Python编程基础入门
- 2024-12-24Python编程基础:变量与数据类型