C++线程池
2021/12/9 17:16:47
本文主要是介绍C++线程池,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
#pragma once #include <vector> #include <queue> #include <memory> #include <thread> #include <mutex> #include <condition_variable> #include <future> #include <functional> #include <stdexcept> class ThreadPool { public: ThreadPool(size_t); template<class F, class... Args> auto enqueue(F&& f, Args&&... args) -> std::future<typename std::result_of<F(Args...)>::type>; ~ThreadPool(); private: // need to keep track of threads so we can join them std::vector< std::thread > workers; // the task queue std::queue< std::function<void()> > tasks; // synchronization std::mutex queue_mutex; std::condition_variable condition; bool stop; }; // the constructor just launches some amount of workers inline ThreadPool::ThreadPool(size_t threads) : stop(false) { for(size_t i = 0;i<threads;++i) workers.emplace_back( [this] { for(;;) { std::function<void()> task; { std::unique_lock<std::mutex> lock(this->queue_mutex); this->condition.wait(lock, [this]{ return this->stop || !this->tasks.empty(); }); if(this->stop && this->tasks.empty()) return; task = std::move(this->tasks.front()); this->tasks.pop(); } task(); } } ); } // add new work item to the pool template<class F, class... Args> auto ThreadPool::enqueue(F&& f, Args&&... args) -> std::future<typename std::result_of<F(Args...)>::type> { using return_type = typename std::result_of<F(Args...)>::type; auto task = std::make_shared< std::packaged_task<return_type()> >( std::bind(std::forward<F>(f), std::forward<Args>(args)...) ); std::future<return_type> res = task->get_future(); { std::unique_lock<std::mutex> lock(queue_mutex); // don't allow enqueueing after stopping the pool if(stop) throw std::runtime_error("enqueue on stopped ThreadPool"); tasks.emplace([task](){ (*task)(); }); } condition.notify_one(); return res; } // the destructor joins all threads inline ThreadPool::~ThreadPool() { { std::unique_lock<std::mutex> lock(queue_mutex); stop = true; } condition.notify_all(); for(std::thread &worker: workers) worker.join(); }
使用方法
#include <iostream> #include <vector> #include <chrono> #include "ThreadPool.h" int main() { ThreadPool pool(4); std::vector< std::future<int> > results; for(int i = 0; i < 8; ++i) { results.emplace_back( pool.enqueue([i] { std::cout << "hello " << i << std::endl; std::this_thread::sleep_for(std::chrono::seconds(1)); std::cout << "world " << i << std::endl; return i*i; }) ); } for(auto && result: results) std::cout << result.get() << ' '; std::cout << std::endl; return 0; }
参考文献
- https://github.com/progschj/ThreadPool
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