2019ICPC沈阳站 E Capture Stars

本文主要是介绍2019ICPC沈阳站 E Capture Stars，对大家解决编程问题具有一定的参考价值，需要的程序猿们随着小编来一起学习吧！

Capture Stars
圆的反演

#pragma GCC optimize(3)
#include<bits/stdc++.h>
using namespace std;
#define y1 y11
#define fi first
#define se second
#define pi acos(-1.0)
#define LL long long
//#define mp make_pair
#define pb push_back
#define ls rt<<1, l, m
#define rs rt<<1|1, m+1, r
#define ULL unsigned LL
#define pll pair<LL, LL>
#define pli pair<LL, int>
#define pii pair<int, int>
#define piii pair<pii, int>
#define pdd pair<double, double>
#define mem(a, b) memset(a, b, sizeof(a))
#define debug(x) cerr << #x << " = " << x << "\n";
#define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
//head
 
const int N = 1e4 + 10;
const double eps = 1e-6; 
int T, n, R, r;
double x[N], y[N];
pdd seg[N];
inline void InvPoint(double &x, double &y) {
	double d = x*x+y*y;
	x = (4.0*R*R)/d*x;
	y = (4.0*R*R)/d*y;
}
int main() {
	scanf("%d", &T);
	while(T--) {
		scanf("%d %d %d", &n, &R, &r);
		for (int i = 1; i <= n; ++i) scanf("%lf %lf", &x[i], &y[i]);
		double fR = 2*R, fr = (4.0*R*R)/(2.0*r), m = (fR+fr)/2, mr = (fr-fR)/2;
		for (int i = 1; i <= n; ++i) {
			InvPoint(x[i], y[i]);
			double dx = fabs(x[i]-m);
			double dy = sqrt(mr*mr-dx*dx);
			seg[i].fi = y[i]-dy;
			seg[i].se = y[i]+dy;
		}
		sort(seg+1, seg+1+n);
		priority_queue<double, vector<double>, greater<double> > q;
		q.push(seg[1].se);
		int ans = 1;
		for (int i = 2; i <= n; ++i) {
			while(!q.empty() && q.top() < seg[i].fi + eps) {
				q.pop();
			}
			q.push(seg[i].se);
			ans = max(ans, (int)q.size());
		}
		printf("%d\n", ans);
	}
	return 0;
}

这篇关于2019ICPC沈阳站 E Capture Stars的文章就介绍到这儿，希望我们推荐的文章对大家有所帮助，也希望大家多多支持为之网！