977. Squares of a Sorted Array
2022/1/6 23:33:34
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Given an integer array nums sorted in non-decreasing order, return an array of the squares of each number sorted in non-decreasing order.
Example 1:
Input: nums = [-4,-1,0,3,10]
Output: [0,1,9,16,100]
Explanation: After squaring, the array becomes [16,1,0,9,100].
After sorting, it becomes [0,1,9,16,100].
Example 2:
Input: nums = [-7,-3,2,3,11]
Output: [4,9,9,49,121]
Constraints:
1 <= nums.length <= 104
-104 <= nums[i] <= 104
nums is sorted in non-decreasing order.
Follow up: Squaring each element and sorting the new array is very trivial, could you find an O(n) solution using a different approach?
Solution:
class Solution { public: vector<int> sortedSquares(vector<int>& nums) { vector<int> result(nums.size()); int le = 0; int ri = nums.size()-1; int length = nums.size()-1; while(le <= ri) { if(abs(nums[le]) > nums[ri]) { result[length] = pow(abs(nums[le]),2); le++; }else{ result[length] = pow(abs(nums[ri]),2); ri--; } length--; } return result; } };
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