C++ Primier Plus(第六版) 第三章 编程练习答案

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本题要求输入转换为不同的格式，实质上考查的是求模和求商。
这里要求使用下滑线指示输入位置，需要使用'\b'使光标向前退，身高以英尺为单位应该是三个数，因此输入三个下划线三个'\b',程序如下：

#include<iostream>
int main()
{
	using namespace std;
	const int inch_per_foot =12;
	int height;
	cout << "Enter your height in inch:___\b\b\b";
	cin >> height;
	int foot = height / inch_per_foot;
	int inch = height % inch_per_foot;
	cout << "Your height is " << foot <<" feet, " <<inch <<" inches."<<endl;
	cin.get();
	cin.get();
	return 0;
}

运行结果如下：

本题考查单位的转换，与第一题类似，身高以几英尺几英寸的方式输入，转换成m需要两步，程序如下：

#include<iostream>
int main()
{
	using namespace std;
	const int inch_per_foot = 12;
	const double meters_per_inch = 0.0254;
	const double pounds_per_kg = 2.2;
	int feet,inches;
	cout << "Enter your height in feet and inches: "<< endl;
	cout << "First, enter feet: __\b\b";
	cin >> feet;
	cout << "Second, enter inches: __\b\b";
	cin >> inches;
	cout << "Enter you weight in pound:___\b\b\b";
	double pounds;
	cin >> pounds;
	int height_inch = feet * inch_per_foot + inches;
	double height_m = height_inch * meters_per_inch;
	double weight = pounds / pounds_per_kg;
	double BMI = weight / (height_m * height_m);

	cout << "Your BMI is " << BMI <<endl;
	cin.get();
	cin.get();
	return 0;
}

运行结果如下:

Enter a latitude in degrees, minutes, and seconds:
First, enter the degrees: 37
Next, enter the minutes of arc: 51
Finally, enter the seconds of arc: 19
37 degrees, 51 minutes, 19seconds = 37.8553 degrees
本题与前两题类似，按照题目要求编写程序即可，程序如下：

#include<iostream>
int main()
{
	using namespace std;
	int degrees, minutes,seconds;
	cout << "Enter a latitude in degrees, minutes, and seconds: " << endl;
	cout << "First, enter the degrees: ";
	cin >> degrees;
	cout << "Next, enter the minutes of arc: ";
	cin >> minutes;
	cout << "Finally, enter the seconds of arc: ";
	cin >> seconds;
	double latitude;
	latitude = degrees + minutes / 60.0 + seconds / 3600.0;
	cout << degrees << " degrees, " << minutes << " minutes, ";
	cout << seconds << " seconds = " << latitude << " degrees" << endl;
	cin.get();
	cin.get();
	return 0;
}

运行结果如下：

Enter the number of seconds: 31600000
31600000 seconds = 365 days, 17 hours, 46 minutes, 40 seconds
本题要求用户输入一个秒数，然后转换为天数+小时数+分钟数+秒数，相当于把之前的英尺+英寸转换为英寸的题目反过来计算，程序如下：

#include<iostream>
int main()
{
	using namespace std;
	long long seconds;
	cout << "Enter the number of seconds: ";
	cin >> seconds;

	int second, minute, hour, days;
	second = seconds % 60;
	long minutes = seconds / 60;
	minute = minutes % 60;
	long hours = minutes / 60;
	hour = hours % 24;
	days = hours / 24;
	
	cout << seconds <<" seconds = " << days <<" days, " << hour;
	cout << " hours, " << minute <<" minutes, " << second << "seconds" <<endl;
	cin.get();
	cin.get();
	return 0;
}

运行结果如下：

Enter the world's population: 6898758899
Enter the population of the US: 310783781
The population of the US is 4.50492% of the world population.
本题要求用户两个人口数目值，计算一个占比，使用百分比显示，程序如下：

#include<iostream>
int main()
{
	using namespace std;
	long long pp_us, pp_world;
	cout << "Enter the worlds's population: ";
	cin >> pp_world;
	cout << "Enter the population of US: ";
	cin >> pp_us;
	double percentage = double(pp_us) / double(pp_world) * 100;
	cout.precision(6);
	cout << "The population of US is " << percentage;
	cout << "% of the world population." <<endl;
	cin.get();
	cin.get();
	return 0;
}

运行结果如下：

本题与前面的计算BMI很类似，程序如下：

//ex6.cpp - - mpg convert to l/100km
#include<iostream>
int main()
{
	using namespace std;
	double m,g; // mlie ,garlon
	cout << "Enter the mile: ";
	cin >> m;
	cout << "Enter the garlon: ";
	cin >> g;
	cout << "The mile per garlon is " << m / g << " mpg." << endl;
	double l = g * 3.875 / (m / 62.14);
	cout << "The fuel consumption is " << l << "L/100Km.";
	cin.get();
	cin.get();
	return 0;
}

运行结果如下：

本题不算难，是第六题的相反过程，程序如下：

//ex6.cpp - - l/100km convert to mpg
#include<iostream>
int main()
{
	using namespace std;
	const double m_per_100km = 62.14;
	const double l_per_g = 3.875;
	double l; // mlie ,garlon
	cout << "Enter the fuel comsuption per 100 km: ";
	cin >> l;
	double m = m_per_100km / (l / l_per_g);
	cout << l <<" L/100km = " << m << " mpg" <<endl;
	cin.get();
	cin.get();
	return 0;
}

运行结果如下：

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