mysql视图
2022/4/27 2:12:48
本文主要是介绍mysql视图,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
-- 视图
-- 准备数据
create database if not exists mydb6_view;
use mydb6_view;
create table dept(
deptno int primary key,
dname varchar(20),
loc varchar(20)
);
insert into dept values(10, '教研部','北京'),
(20, '学工部','上海'),
(30, '销售部','广州'),
(40, '财务部','武汉');
create table emp(
empno int primary key,
ename varchar(20),
job varchar(20),
mgr int,
hiredate date,
sal numeric(8,2),
comm numeric(8, 2),
deptno int,
-- FOREIGN KEY (mgr) REFERENCES emp(empno),
FOREIGN KEY (deptno) REFERENCES dept(deptno) ON DELETE SET NULL ON UPDATE CASCADE
);
insert into emp values
(1001, '甘宁', '文员', 1013, '2000-12-17', 8000.00, null, 20),
(1002, '黛绮丝', '销售员', 1006, '2001-02-20', 16000.00, 3000.00, 30),
(1003, '殷天正', '销售员', 1006, '2001-02-22', 12500.00, 5000.00, 30),
(1004, '刘备', '经理', 1009, '2001-4-02', 29750.00, null, 20),
(1005, '谢逊', '销售员', 1006, '2001-9-28', 12500.00, 14000.00, 30),
(1006, '关羽', '经理', 1009, '2001-05-01', 28500.00, null, 30),
(1007, '张飞', '经理', 1009, '2001-09-01', 24500.00, null, 10),
(1008, '诸葛亮', '分析师', 1004, '2007-04-19', 30000.00, null, 20),
(1009, '曾阿牛', '董事长', null, '2001-11-17', 50000.00, null, 10),
(1010, '韦一笑', '销售员', 1006, '2001-09-08', 15000.00, 0.00, 30),
(1011, '周泰', '文员', 1008, '2007-05-23', 11000.00, null, 20),
(1012, '程普', '文员', 1006, '2001-12-03', 9500.00, null, 30),
(1013, '庞统', '分析师', 1004, '2001-12-03', 30000.00, null, 20),
(1014, '黄盖', '文员', 1007, '2002-01-23', 13000.00, null, 10);
create table salgrade(
grade int primary key,
losal int,
hisal int
);
insert into salgrade values
(1, 7000, 12000),
(2, 12010, 14000),
(3, 14010, 20000),
(4, 20010, 30000),
(5, 30010, 99990);
-- 创建视图
CREATE
OR REPLACE VIEW view1_emp AS SELECT
ename,
job
FROM
emp;
-- 查看表和视图
show tables;
show full tables;
-- 查看视图结构
DESCRIBE view1_emp;
-- 查询视图
SELECT
*
FROM
view1_emp;
-- 修改视图结构
ALTER VIEW view1_emp AS SELECT
a.deptno,
a.dname,
a.loc,
b.ename,
b.sal
FROM
dept a,
emp b
WHERE
a.deptno = b.deptno;
-- 更新视图:修改原表数据
-- 先创建一个视图
CREATE
OR REPLACE VIEW view1_emp AS SELECT
ename,
job
FROM
emp;
-- 查询一下视图
SELECT
*
FROM
view1_emp;
-- 更新视图
UPDATE view1_emp
SET ename = '鲁肃'
WHERE
ename = '谢逊';
-- 1、插入数据时,视图只是引用表格中的某些字段,
-- 而另外一些字段又没有指定默认值时会插入失败
INSERT INTO view1_emp
VALUES
( '周瑜', '文员' );
-- 2、视图包含聚合函数不可更新
CREATE
OR REPLACE VIEW view2_emp AS SELECT
count(*) cnt
FROM
emp;
SELECT
*
FROM
view2_emp;
INSERT INTO view2_emp
VALUES
( 100 );
UPDATE view2_emp
SET cnt = 100;
-- 3、视图包含distinct不可更新
CREATE
OR REPLACE VIEW view3_emp AS SELECT DISTINCT
job
FROM
emp;
SELECT
*
FROM
view3_emp;
INSERT INTO view3_emp
VALUES
( '财务' );
-- 4、视图包含group by、having不可更新
CREATE
OR REPLACE VIEW view4_emp AS SELECT
deptno
FROM
emp
GROUP BY
deptno
HAVING
deptno > 10;
SELECT
*
FROM
view4_emp;
insert into view4_emp values(40);
-- 5、视图包含union、union all不可更新
-- union all不去重,union会去重
CREATE
OR REPLACE VIEW view5_emp AS SELECT
empno,
ename
FROM
emp
WHERE
empno <= 5 UNION SELECT empno, ename FROM emp WHERE empno > 8;
SELECT
*
FROM
view5_emp;
INSERT INTO view5_emp
VALUES
( 1015, '宋江' );
-- 6、视图包含子查询不可更新
CREATE
OR REPLACE VIEW view6_emp AS SELECT
empno,
ename,
sal
FROM
emp
WHERE
sal = (
SELECT
max( sal )
FROM
emp);
SELECT
*
FROM
view6_emp;
INSERT INTO view6_emp
VALUES
( 1015, '血刀老祖', 30000.0 );
-- 7、视图包含join不可更新
CREATE VIEW view7_emp AS SELECT
dname,
ename,
sal
FROM
emp a
JOIN dept b ON a.deptno = b.deptno;
INSERT INTO view7_emp
VALUES
( '行政部', '韦小宝', 6500.00 );
-- 8、视图包含常量文字值不可更新
CREATE
OR REPLACE VIEW view8_emp AS SELECT
'行政部' dname,
'杨过' ename;
INSERT INTO view8_emp
VALUES
( '行政部', '韦小宝' );
CREATE
OR REPLACE VIEW view9_emp AS SELECT
*
FROM
emp;
-- 重命名视图
RENAME TABLE view9_emp TO view9_1_emp;
-- 删除视图
DROP VIEW
IF
EXISTS view9_1_emp;
-- 视图练习
-- 1:查询部门平均薪水最高的部门名称
-- 最原始做法:不使用开窗函数,不使用视图
SELECT
dname
FROM
dept
WHERE
deptno = (
SELECT
b.deptno
FROM
(
SELECT
a.deptno,
max( a.avg_sal )
FROM
( SELECT deptno, avg( sal ) avg_sal FROM emp GROUP BY deptno ) a
) b
);
-- 1:增加一点难度查询部门平均薪水处于最高两位的部门名称
-- 使用开窗函数,不使用视图
-- 1.1 先查出每个部门编号对应的平均薪水
-- 1.2 用开窗函数进行排序
-- 1.3 找到rank小于等于2的deptno
-- 1.4 再跟dept表联合查找出dname
SELECT
dname
FROM
dept d,
(
SELECT
deptno
FROM
(
SELECT
*,
rank() over ( ORDER BY avg_sal DESC ) rn
FROM
( SELECT deptno, avg( sal ) avg_sal FROM emp GROUP BY deptno ) a
) b
WHERE
rn = 1
) c
WHERE
d.deptno = c.deptno;
-- 1:增加一点难度查询部门平均薪水处于最高两位的部门名称
-- 使用开窗函数,并且使用视图
-- 1.1 先查出每个部门编号对应的平均薪水,创建一个视图
CREATE
OR REPLACE VIEW view_dept_avg_sal AS SELECT
deptno,
avg( sal ) avg_sal
FROM
emp
GROUP BY
deptno;
-- 1.2 用开窗函数进行排序,创建一个视图
CREATE
OR REPLACE VIEW view_dept_avg_sal_rank AS SELECT
*,
rank() over ( ORDER BY avg_sal DESC ) rn
FROM
view_dept_avg_sal;
-- 1.3 找到rank小于等于2的deptno,创建一个视图
CREATE
OR REPLACE VIEW view_dept_avg_sal_top2 AS SELECT
*
FROM
view_dept_avg_sal_rank
WHERE
rn <= 2;
-- 1.4 再跟dept表联合查找出dname
CREATE
OR REPLACE VIEW view_dept_avg_sal_top2_dname AS SELECT
dname
FROM
dept a,
view_dept_avg_sal_top2 b
WHERE
a.deptno = b.deptno;
-- 2:查询员工比所属领导薪资高的部门名、员工名、员工领导编号
-- 最原始做法:不使用视图
SELECT
dname,
ename,
mgr
FROM
dept b,
(
SELECT
e1.deptno,
e1.ename,
e1.sal,
e1.mgr,
e2.sal mgr_sal
FROM
emp e1,
emp e2
WHERE
e1.mgr = e2.empno
AND e1.sal > e2.sal
) a
WHERE
b.deptno = a.deptno;
-- 2:查询员工比所属领导薪资高的部门名、员工名、员工领导编号
-- 使用视图
-- 2.1查询员工比所属领导薪资高的部门号,然后创建一个视图
CREATE
OR REPLACE VIEW view_deptno_ename_mgr AS SELECT
e1.deptno,
e1.ename,
e1.mgr
FROM
emp e1,
emp e2
WHERE
e1.mgr = e2.empno and e1.sal > e2.sal;
-- 2.2将上一步查询出来的部门号和部门表进行连表查询
CREATE
OR REPLACE VIEW view_dname_ename_mgr AS SELECT
dname,
ename,
mgr
FROM
dept a,
view_deptno_ename_mgr b
WHERE
a.deptno = b.deptno;
-- 3:查询工资等级为4级,2000年以后入职的工作地点为上海的员工编号、姓名和工资,
-- 并查询出薪资在前2名的员工信息
-- 最原始做法,不使用视图
SELECT
empno,
ename,
sal
FROM
(
SELECT
empno,
ename,
sal,
rank() over ( ORDER BY sal DESC ) rn
FROM
emp e,
dept d,
salgrade s
WHERE
e.deptno = d.deptno
AND YEAR ( hiredate ) >= '2000'
AND loc = '上海'
AND grade = 4
AND sal BETWEEN losal
AND hisal
) a
WHERE
rn <= 2;
-- 3:查询工资等级为4级,2000年以后入职的工作地点为上海的员工编号、姓名和工资,
-- 并查询出薪资在前2名的员工信息
-- 使用视图
-- 3.1 查询工资等级为4级,2000年以后入职的工作地点为上海的员工编号、姓名和工资,创建一个视图
CREATE
OR REPLACE VIEW view_ename_sal_after2000_grade4 AS SELECT
empno, ename, sal
FROM
emp e,
dept d,
salgrade s
WHERE
e.deptno = d.deptno
AND grade = 4
AND sal BETWEEN losal
AND hisal
AND loc = '上海'
AND YEAR ( hiredate ) > '2000'
-- 此处三张表联查还可以用join,逻辑会更清晰
SELECT
empno,
ename,
sal
FROM
emp e
JOIN dept d ON e.deptno = d.deptno AND loc = '上海' AND YEAR ( hiredate ) > '2000';
JOIN salgrade s ON grade = 4 AND ( sal BETWEEN losal AND hisal )
-- 3.2 查询出薪资在前2名的员工信息
SELECT
empno,
ename,
sal
FROM
( SELECT *, rank() over ( ORDER BY sal DESC ) rn FROM view_ename_sal_after2000_grade4 ) a
WHERE
rn <= 2;
这篇关于mysql视图的文章就介绍到这儿,希望我们推荐的文章对大家有所帮助,也希望大家多多支持为之网!
- 2024-11-04部署MySQL集群项目实战:新手入门教程
- 2024-11-04如何部署MySQL集群资料:新手入门指南
- 2024-11-02MySQL集群项目实战:新手入门指南
- 2024-11-02初学者指南:部署MySQL集群资料
- 2024-11-01部署MySQL集群教程:新手入门指南
- 2024-11-01如何部署MySQL集群:新手入门教程
- 2024-11-01部署MySQL集群学习:新手入门教程
- 2024-11-01部署MySQL集群入门:新手必读指南
- 2024-10-23BinLog入门:新手必读的MySQL二进制日志指南
- 2024-10-23Binlog入门:MySQL数据库的日志管理指南