C 语言实例 - 斐波那契数列
C 语言实例斐波那契数列指的是这样一个数列 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233，377，610，987，1597，2584，4181，6765，10946，17711，28657，46368........
这个数列从第3项开始，每一项都等于前两项之和。
实例 - 输出指定数量的斐波那契数列
#include <stdio.h>
int main()
{
int i, n, t1 = 0, t2 = 1, nextTerm;
printf("输出几项: ");
scanf("%d", &n);
printf("斐波那契数列: ");
for (i = 1; i <= n; ++i)
{
printf("%d, ", t1);
nextTerm = t1 + t2;
t1 = t2;
t2 = nextTerm;
}
return 0;
}
运行结果：
输出几项: 10 斐波那契数列: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34,
实例 - 输出指定数字前的斐波那契数列
#include <stdio.h>
int main()
{
int t1 = 0, t2 = 1, nextTerm = 0, n;
printf("输入一个正数: ");
scanf("%d", &n);
// 显示前两项
printf("斐波那契数列: %d, %d, ", t1, t2);
nextTerm = t1 + t2;
while(nextTerm <= n)
{
printf("%d, ",nextTerm);
t1 = t2;
t2 = nextTerm;
nextTerm = t1 + t2;
}
return 0;
}
运行结果：
输入一个正数: 100 斐波那契数列: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89,
