搜索结果
查询Tags标签： Leaves，共有 8条记录-
Python - Get leaves count in a dictionary
def get_dict_leaves_count(dic):if len(dic) == 0:return 0else:cnt = 0for k, v in dic.items():if not isinstance(v, Mapping):cnt += 1else:cnt += get_dict_leaves_count(v)return cnt
2022/1/24 1:04:24 人评论 次浏览 -
【数据结构】算法 层数最深叶子节点的和 Deepest Leaves Sum
目录层数最深叶子节点的和 Deepest Leaves Sum思路Tag 层数最深叶子节点的和 Deepest Leaves Sum 一棵二叉树的根节点root,返回层数最深的叶子节点的和。in： root = [1,2,3,4,5,null,6,7,null,null,null,null,8] out：15思路 对树的处理基本就是 DFS,BFS。 看到一个非常有…
2021/10/19 1:09:21 人评论 次浏览 -
【数据结构】算法 层数最深叶子节点的和 Deepest Leaves Sum
目录层数最深叶子节点的和 Deepest Leaves Sum思路Tag 层数最深叶子节点的和 Deepest Leaves Sum 一棵二叉树的根节点root,返回层数最深的叶子节点的和。in： root = [1,2,3,4,5,null,6,7,null,null,null,null,8] out：15思路 对树的处理基本就是 DFS,BFS。 看到一个非常有…
2021/10/19 1:09:21 人评论 次浏览 -
1004 Counting Leaves (30 分)
1004 Counting Leaves (30 分) A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one test case. Each case starts with a line containing …
2021/9/19 23:35:52 人评论 次浏览 -
1004 Counting Leaves (30 分)
1004 Counting Leaves (30 分) A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one test case. Each case starts with a line containing …
2021/9/19 23:35:52 人评论 次浏览 -
[2021 spring] CS61A Lab 5: Python Lists, Data Abstraction, Trees
lab05： https://inst.eecs.berkeley.edu/~cs61a/sp21/lab/lab05/#topics lab5包括对列表的理解，数据抽象，和树 目录TopicsList ComprehensionsData AbstractionTreesRequired QuestionsQ1: Couple(List Comprehensions)Q2: Distance(Data Abstraction)Q3: Closer city(…
2021/6/29 9:52:47 人评论 次浏览 -
浙大PTA 编程题 03-树2 List Leaves (25 分)（c++）
思路： 这道题的意思就是：按照层序来输出叶结点。因为是按照层序，所以遍历树中元素的方式就不同于树的同构了，因为遍历完左儿子1，不能遍历左儿子1的左儿子2，而是要遍历和左儿子1并列的右儿子1，这就需要我们记住左儿子1的父亲，才能找到右儿子1，这样用结构数组来编程…
2021/6/27 22:20:23 人评论 次浏览 -
PAT——Counting Leaves（使用vector和bfs算法）
Counting Leaves 题目答案题目答案 #include<iostream> #include<cstring> #include<vector> #include<queue> using namespace std; vector<int> vec[101];void bfs(int root) {if(vec[root].size()==0) {cout<<1;return;}else cou…
2021/4/28 20:55:32 人评论 次浏览
