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查询Tags标签： Parentheses，共有 10条记录-
[LeetCode] 2116. Check if a Parentheses String Can Be Valid
A parentheses string is a non-empty string consisting only of ( and ). It is valid if any of the following conditions is true:It is (). It can be written as AB (A concatenated with B), where A and B are valid parentheses strings. It can be written as …
2022/7/2 6:20:07 人评论 次浏览 -
判断括号是否匹配–python
例子：valid_parentheses(i(hi)()) == True valid_parentheses(hi())() == False valid_parentheses() == True valid_parentheses(())(())) == False实现： 方法一：def valid_parentheses(string):cnt = 0for char in string:if char == (: cnt += 1if char == ): cnt -…
2022/5/28 1:24:14 人评论 次浏览 -
301. Remove Invalid Parentheses
Just use BFS to solve this problem: 1. put the s to queue 2. if s is not a valid string, then remove a ( or ), and then put to the queue. 3. once find valid strings, return.class Solution {public List<String> removeInvalidParentheses(String s) {…
2022/4/7 6:20:47 人评论 次浏览 -
921. Minimum Add to Make Parentheses Valid
这道题是典型的括号题，一般来说，括号题用stack做，但是这道题因为太简单了，连stack都不用， 就用int就好了，时间复杂度O(n)。public int minAddToMakeValid(String s) {int count = 0;int res = 0;for(int i=0;i<s.length();i++){char c = s.charAt(i);if(c==(){co…
2022/1/28 6:04:16 人评论 次浏览 -
LeetCode 20. 有效的括号(Valid Parentheses)
20. 有效的括号给定一个只包括 (，)，{，}，[，] 的字符串 s ，判断字符串是否有效。 有效字符串需满足：左括号必须用相同类型的右括号闭合。 左括号必须以正确的顺序闭合。Given a string s containing just the characters (, ), {, }, [ and ], determine if the inpu…
2021/8/23 23:06:10 人评论 次浏览 -
LeetCode 20. 有效的括号(Valid Parentheses)
20. 有效的括号给定一个只包括 (，)，{，}，[，] 的字符串 s ，判断字符串是否有效。 有效字符串需满足：左括号必须用相同类型的右括号闭合。 左括号必须以正确的顺序闭合。Given a string s containing just the characters (, ), {, }, [ and ], determine if the inpu…
2021/8/23 23:06:10 人评论 次浏览 -
[LeetCode] 1190. Reverse Substrings Between Each Pair of Parentheses 反转每对括号间的子串
You are given a string s that consists of lower case English letters and brackets. Reverse the strings in each pair of matching parentheses, starting from the innermost one. Your result should not contain any brackets. Example 1: Input: s = "(abc…
2021/8/15 6:05:45 人评论 次浏览 -
[LeetCode] 1190. Reverse Substrings Between Each Pair of Parentheses 反转每对括号间的子串
You are given a string s that consists of lower case English letters and brackets. Reverse the strings in each pair of matching parentheses, starting from the innermost one. Your result should not contain any brackets. Example 1: Input: s = "(abc…
2021/8/15 6:05:45 人评论 次浏览 -
LeetCode-020-有效的括号
有效的括号题目描述：给定一个只包括 (，)，{，}，[，] 的字符串 s ，判断字符串是否有效。 有效字符串需满足： 左括号必须用相同类型的右括号闭合。 左括号必须以正确的顺序闭合。 示例说明请见LeetCode官网。 来源：力扣（LeetCode） 链接：https://leetcode-cn.com/pr…
2021/6/25 23:30:11 人评论 次浏览 -
算法：22. Generate Parentheses生成配对括号
22. Generate Parentheses Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. Example 1: Input: n = 3 Output: ["((()))","(()())","(())()","()(())","()()()&…
2021/6/22 14:27:08 人评论 次浏览
