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[CodeForces] D. Make The Fence Great Again
ProblemEach fence is increased at most 2 times, so dp[i][j] is the min cost to make A[0, i] great with the last fence A[i] increased j times. The answer is min of dp[n - 1][].
2022/1/18 6:34:24 人评论 次浏览 -
[CodeForces] D. Make The Fence Great Again
ProblemEach fence is increased at most 2 times, so dp[i][j] is the min cost to make A[0, i] great with the last fence A[i] increased j times. The answer is min of dp[n - 1][].
2022/1/18 6:34:24 人评论 次浏览