python代码实现凯撒加解密
2021/10/15 1:15:59
本文主要是介绍python代码实现凯撒加解密,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
import string letter = string.ascii_letters mark = string.punctuation def main(): while True: print("输入数字1为凯撒加密,输入数字2为凯撒解密,输入0退出!") choice = int(input('请输入相应数值:')) if choice == 1: kaisa_jiami() elif choice == 2: kaisa_jiemi() elif choice == 0: break else: print('请输入正确的数值!') continue def kaisa_jiami(): k = int(input('请输入一个整数密匙:')) a = input('请输入要加密的字符串:') list = [] for i in range(len(a)): if a[i] in letter: b = 97 + ((ord(a[i])-97 + k)%26) b = chr(b) elif a[i] in mark: b = a[i] else: b = a[i] list.append(b) print('加密后的密码:{}'.format(''.join(list))) def kaisa_jiemi(): k = int(input('请输入一个整数密匙:')) a = input('请输入要解密的字符串:') list = [] for i in range(len(a)): if a[i] in letter: b = 97 + ((ord(a[i])-97 - k)%26) b = chr(b) elif a[i] in mark: b = a[i] else: b = a[i] list.append(b) print('解密后的密码:{}'.format(''.join(list))) if __name__ == '__main__': main()
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