python用来获得图片exif信息的库源码
2021/11/16 9:09:54
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library test/debug function (dump given files)
if name == 'main':
import sys
import getopt
# parse command line options/arguments try: opts, args = getopt.getopt(sys.argv[1:], "hqsdt:v", ["help", "quick", "strict", "debug", "stop-tag="]) except getopt.GetoptError: usage(2) if args == []: usage(2) detailed = True stop_tag = 'UNDEF' debug = False strict = False for o, a in opts: if o in ("-h", "--help"): usage(0) if o in ("-q", "--quick"): detailed = False if o in ("-t", "--stop-tag"): stop_tag = a if o in ("-s", "--strict"): strict = True if o in ("-d", "--debug"): debug = True # output info for each file for filename in args: try: file=open(filename, 'rb') except: print "'%s' is unreadablen"%filename continue print filename + ':' # get the tags data = process_file(file, stop_tag=stop_tag, details=detailed, strict=strict, debug=debug) if not data: print 'No EXIF information found' continue x=data.keys() x.sort() for i in x: if i in ('JPEGThumbnail', 'TIFFThumbnail'): continue try: print ' %s (%s): %s' % (i, FIELD_TYPES[data[i].field_type][2], data[i].printable) except: print 'error', i, '"', data[i], '"' if 'JPEGThumbnail' in data: print 'File has JPEG thumbnail' print <h4>附件:<a href="/uploadfiles/2013/09/24/137998571444528.zip">源代码下载</a></h4>
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