链表排序 python 力扣148
2022/1/14 9:03:33
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力扣148 https://leetcode-cn.com/problems/sort-list/
归并排序单向链表 完整解法
# from utils import ListNode, LinkList from typing import List class ListNode(object): def __init__(self, val=None, next=None): self.val = val self.next = next def __repr__(self): res = '' p = self.next res = '' + str(self.val) + '-->' while p: tmp = str(p.val) tmp = tmp + '-->' if p.next else tmp res += tmp p = p.next return res def LinkList(lst: List) -> ListNode: if not lst: return None head = ListNode(lst[0]) p = head for i in range(1, len(lst)): p.next = ListNode(lst[i]) p = p.next return head def sortList(head: ListNode) -> ListNode: if not head or not head.next: return head slow, fast = head, head.next # find the mid and cut the LinkList while fast and fast.next: slow, fast = slow.next, fast.next.next mid, slow.next = slow.next, None left, right = sortList(head), sortList(mid) # merge two sorted LinkList dummy = ListNode(0) p = dummy while left and right: if left.val < right.val: p.next, left = left, left.next else: p.next, right = right, right.next p = p.next p.next = left if left else right return dummy.next if __name__ == "__main__": ins = LinkList([1, 6, 3, 9, 7, 5]) print(ins) outs = sortList(ins) print(outs)
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