python实现简单点对点(p2p)聊天
2019/7/13 22:48:27
本文主要是介绍python实现简单点对点(p2p)聊天,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
点对点聊天首先是基于多线程的网络编程,其次就是将每一个连接都保存为一个具有独一属性的对象并添加到连接列表中,对于每一个连接对象发送过来的信息必须要包含主要的三项内容(from,to,messages),这样当信息发送到服务器之后服务器根据to的连接对象遍历连接列表找到目标对象将信息发送给目标,目标拿到信息后就知道是谁发过来的,然后根据id号码进行回复。此实现将会继续完善,后续新加功能将会在我个人github主页展现
服务器端实现:
#coding:utf-8 ''' file:server.py date:2017/9/10 12:43 author:lockey email:lockey@123.com platform:win7.x86_64 pycharm python3 desc:p2p communication serverside ''' import socketserver,json import subprocess connLst = [] ## 连接列表,用来保存一个连接的信息(代号 地址和端口 连接对象) class Connector(object):#连接对象类 def __init__(self,account,password,addrPort,conObj): self.account = account self.password = password self.addrPort = addrPort self.conObj = conObj class MyServer(socketserver.BaseRequestHandler): def handle(self): print("got connection from",self.client_address) register = False while True: conn = self.request data = conn.recv(1024) if not data: continue dataobj = json.loads(data.decode('utf-8')) #如果连接客户端发送过来的信息格式是一个列表且注册标识为False时进行用户注册 if type(dataobj) == list and not register: account = dataobj[0] password = dataobj[1] conObj = Connector(account,password,self.client_address,self.request) connLst.append(conObj) register = True continue print(connLst) #如果目标客户端在发送数据给目标客服端 if len(connLst) > 1 and type(dataobj) == dict: sendok = False for obj in connLst: if dataobj['to'] == obj.account: obj.conObj.sendall(data) sendok = True if sendok == False: print('no target valid!') else: conn.sendall('nobody recevied!'.encode('utf-8')) continue if __name__ == '__main__': server = socketserver.ThreadingTCPServer(('192.168.1.4',8022),MyServer) print('waiting for connection...') server.serve_forever()
客户端实现:
#coding:utf-8 ''' file:client.py.py date:2017/9/10 11:01 author:lockey email:lockey@123.com platform:win7.x86_64 pycharm python3 desc:p2p communication clientside ''' from socket import * import threading,sys,json,re HOST = '192.168.1.4' ## PORT=8022 BUFSIZ = 1024 ##缓冲区大小 1K ADDR = (HOST,PORT) tcpCliSock = socket(AF_INET,SOCK_STREAM) tcpCliSock.connect(ADDR) userAccount = None def register(): myre = r"^[_a-zA-Z]\w{0,}" #正则验证用户名是否合乎规范 accout = input('Please input your account: ') if not re.findall(myre, accout): print('Account illegal!') return None password1 = input('Please input your password: ') password2 = input('Please confirm your password: ') if not (password1 and password1 == password2): print('Password not illegal!') return None global userAccount userAccount = accout return (accout,password1) class inputdata(threading.Thread): def run(self): while True: sendto = input('to>>:') msg = input('msg>>:') dataObj = {'to':sendto,'msg':msg,'froms':userAccount} datastr = json.dumps(dataObj) tcpCliSock.send(datastr.encode('utf-8')) class getdata(threading.Thread): def run(self): while True: data = tcpCliSock.recv(BUFSIZ) dataObj = json.loads(data.decode('utf-8')) print('{} -> {}'.format(dataObj['froms'],dataObj['msg'])) def main(): while True: regInfo = register() if regInfo: datastr = json.dumps(regInfo) tcpCliSock.send(datastr.encode('utf-8')) break myinputd = inputdata() mygetdata = getdata() myinputd.start() mygetdata.start() myinputd.join() mygetdata.join() if __name__ == '__main__': main()
运行结果示例:
服务器端结果:
客户端1:
客户端2:
客户端3:
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持找一找教程网。
这篇关于python实现简单点对点(p2p)聊天的文章就介绍到这儿,希望我们推荐的文章对大家有所帮助,也希望大家多多支持为之网!
- 2024-11-02Python编程基础
- 2024-11-01Python 基础教程
- 2024-11-01用Python探索可解与不可解方程的问题
- 2024-11-01Python编程入门指南
- 2024-11-01Python编程基础知识
- 2024-11-01Python编程基础
- 2024-10-31Python基础入门:理解变量与数据类型
- 2024-10-30Python股票自动化交易资料详解与实战指南
- 2024-10-30Python入行:新手必读的Python编程入门指南
- 2024-10-30Python入行:初学者必备的编程指南